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Snowflake SOL-C01 Exam Syllabus Topics:
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Valid SOL-C01 Test Cram | SOL-C01 Free Study Material
This version is designed especially for those SOL-C01 test takers who cannot go through extensive Snowflake SOL-C01 practice sessions due to a shortage of time. Since the Snowflake SOL-C01 PDF file works on smartphones, laptops, and tablets, one can use Snowflake SOL-C01 dumps without limitations of place and time. Additionally, these Snowflake SOL-C01 PDF questions are printable as well.
Snowflake Certified SnowPro Associate - Platform Certification Sample Questions (Q185-Q190):
NEW QUESTION # 185
You have a table 'PRODUCT_PRICES' defined as 'CREATE TABLE PRODUCT_PRICES (PRODUCT_ID INT, PRICE LAST UPDATED TIMESTAMP NTZ)'. You want to insert new prices for some products, but only if the new price is different from the existing price. If the price is the same, you want to update the 'LAST UPDATED' timestamp. Which of the following approaches would be the most efficient in Snowflake to achieve this?
- A. Perform a 'SELECT statement for each 'PRODUCT_ID to check the existing price, then either
'INSERT or 'UPDATE accordingly. - B. First 'INSERT all the new prices into a temporary table, then use a 'JOIN' with the original table to identify the rows that need to be updated or inserted.
- C. Create a new table with all the product IDs that need to be updated and use 'INSERT OVERWRITE to replace original table.
- D. Use `MERGE statement to update the 'LAST UPDATED timestamp and insert new records if a record for the 'PRODUCT ID does not exist.
- E. Use a stored procedure that iterates through the new data and performs 'INSERT or 'UPDATE statements based on the existing price.
Answer: D
Explanation:
Option C is the most efficient because the 'MERGE statement is specifically designed for scenarios where you need to conditionally insert or update data based on a join condition. It avoids the overhead of multiple `SELECT statements or a stored procedure iterating through the data. A and B perform row-by- row operations which is slow in Snowflake. Although D is valid, it requires you to create temporary tables, populate and then join against the original table, which takes more time and code. Option E overwrites the whole table which is not needed since we only need to update records if a record for the 'PRODUCT_ID' does not exist.
NEW QUESTION # 186
What will be returned when a user runs this command?
SELECT count FROM my_table LIMIT 10;
- A. A non-deterministic set of 10 values in the count column.
- B. All values in the count column that are less than or equal to 10.
- C. The lowest 10 values in the count column.
- D. The highest 10 values in the count column.
Answer: A
Explanation:
When a LIMIT clause is applied without an ORDER BY, Snowflake does not guarantee which rows will be returned. This means the result of:
SELECT count FROM my_table LIMIT 10;
is anon-deterministic set of 10 rows. Because Snowflake stores data in micro-partitions and distributes processing across compute resources, the natural order of rows is undefined unless explicitly controlled.
To retrieve the lowest or highest values, users must specify ORDER BY count ASC or ORDER BY count DESC respectively. Without ordering, Snowflake simply returnsany10 qualifying rows.
* Option B (highest values) requires ORDER BY count DESC.
* Option D (lowest values) requires ORDER BY count ASC.
* Option C (values # 10) requires a WHERE clause (WHERE count <= 10).
Therefore, the query returns a non-predictable sample of 10 rows from the column, making option A correct.
NEW QUESTION # 187
Consider the following SQL code snippet intended to insert data into a Snowflake table named
'employees'. However, the execution results in a data type mismatch error. Analyze the code and identify the root cause of the error. Assume the 'salary' column in the 'employees' table is defined as NUMBER(10,2).
- A. The 'dept_id' is not a valid integer value.
- B. The date format 'YYYY-MM-DD' is incorrect for the 'hire date' column.
- C. The 'insert' statement is missing the column names explicitly.
- D. The string 'Five Thousand' cannot be implicitly converted to a NUMBER(10,2) for the 'salary' column.
- E. The semi-colon (;) at the end of the VALUES clause is causing a syntax error.
Answer: D
Explanation:
The error is due to attempting to insert the string 'Five Thousand' into the 'salary' column, which is defined as NUMBER(10,2). Snowflake cannot implicitly convert a string representation of a number written in words to a numerical value. All other options are syntactically correct or would result in different types of errors.
NEW QUESTION # 188
You are tasked with creating a development environment from a production database in Snowflake. The production database,
'PROD DB', is very large and you need to minimize the storage costs and time required for the cloning operation. The development environment should be isolated and allow developers to make changes without affecting production data. Which of the following approaches is the most efficient and cost- effective?
- A. Create a full clone of 'PROD_Dff using 'CREATE DATABASE DEV_DB CLONE PROD_DB;'
- B. Export the data from 'PROD to cloud storage, create a new database 'DEV DBS, and import the data.Then grant access to developers.
- C. Create a zero-copy clone of 'PROD DB' using 'CREATE DATABASE DEV DB CLONE PROD DB;'
- D. Create a full backup of restore it to a new database 'DEV_DB', and then grant access to developers.
- E. Create a zero-copy clone of 'PROD_DB' using 'CREATE DATABASE DEV_DB CLONE PROD_DB BEFORE (TIMESTAMP '2023-01-01 and then grant access to developers.
Answer: C
Explanation:
Snowflake cloning is a zero-copy operation. Using 'CREATE DATABASE DEV_DB CLONE PROD_DB',' creates a metadata copy instantly. The storage is only consumed when changes are made to the cloned database 'DEV DBA. This is the most efficient and cost-effective method. A, D, and E involve full data duplication which is slower and more expensive. C is also zero copy cloning but refers to a specific timestamp, which wasn't a requirement of the question.
NEW QUESTION # 189
Which of the following are date and time data types in Snowflake? (Choose any 3 options)
- A. DATE
- B. TIMESTAMP
- C. DATETIME
- D. JavaScript
- E. TIMEDATE
- F. Python
Answer: A,B,C
Explanation:
Snowflake supports several native data types for managing temporal information:
DATE - Stores dates only (year, month, day) without any time component.
TIMESTAMP - Represents date and time values, including several variants:
* TIMESTAMP_NTZ (no time zone)
* TIMESTAMP_LTZ (local time zone)
* TIMESTAMP_TZ (explicit time zone)
DATETIME - An alias for TIMESTAMP_NTZ, storing both date and time.
These data types enable powerful time-based analytics and comparisons.
#TIMEDATE is not a valid data type.
#Python and JavaScript are programming languages, not Snowflake data types.
NEW QUESTION # 190
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